3(2x^2+5)=5(3x^2-2)

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Solution for 3(2x^2+5)=5(3x^2-2) equation:


Simplifying
3(2x2 + 5) = 5(3x2 + -2)

Reorder the terms:
3(5 + 2x2) = 5(3x2 + -2)
(5 * 3 + 2x2 * 3) = 5(3x2 + -2)
(15 + 6x2) = 5(3x2 + -2)

Reorder the terms:
15 + 6x2 = 5(-2 + 3x2)
15 + 6x2 = (-2 * 5 + 3x2 * 5)
15 + 6x2 = (-10 + 15x2)

Solving
15 + 6x2 = -10 + 15x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-15x2' to each side of the equation.
15 + 6x2 + -15x2 = -10 + 15x2 + -15x2

Combine like terms: 6x2 + -15x2 = -9x2
15 + -9x2 = -10 + 15x2 + -15x2

Combine like terms: 15x2 + -15x2 = 0
15 + -9x2 = -10 + 0
15 + -9x2 = -10

Add '-15' to each side of the equation.
15 + -15 + -9x2 = -10 + -15

Combine like terms: 15 + -15 = 0
0 + -9x2 = -10 + -15
-9x2 = -10 + -15

Combine like terms: -10 + -15 = -25
-9x2 = -25

Divide each side by '-9'.
x2 = 2.777777778

Simplifying
x2 = 2.777777778

Take the square root of each side:
x = {-1.666666667, 1.666666667}

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